E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
At least your school provides them. I already had a camera that I bought in HS when I started college, but those who didn't had to go out and spend over $100 and buy one. Of course, my school does have other cameras to borrow, just not 35mm.
Hee hee... There's nothing digital about this camera. All that there is, is a little timy battery that tells me whether or not there's too much or not enough light. Also, there are no lenses that I can borrow from the school, which is my only means of surviving Basic Photo. ( =^D))
--
It's not the fact that I died that bothers me, it's just that you didn't watch me suffer.
I work at a camera store. It makes it much less pricey. The pay is poor, but the money you save is great. The 4x5 isn't mine, but I have unlimited borrowing power.
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
Hi Welcome to DA
This is a lovely place. I’m sure u will like it a lot
-Priyantha
----------------------------------------------------------------------------------------------
My page is [link]
Have a look when u get some free time and tell me what u think of it!
Devious Comments
--
Did you know that:
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
--
It's not the fact that I died that bothers me, it's just that you didn't watch me suffer.
--
It's not the fact that I died that bothers me, it's just that you didn't watch me suffer.
thank you for faving my Lomion V , also for your kind words and finally watching my arts
Angel
--
"Zu den seltenen Zeiten, in denen wir einen anderen Menschen berühren,tragen wir Handschuhe" Gil Grissom ~ CSI
--
Did you know that:
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
--
It's not the fact that I died that bothers me, it's just that you didn't watch me suffer.
This is a lovely place. I’m sure u will like it a lot
-Priyantha
----------------------------------------------------------------------------------------------
My page is [link]
Have a look when u get some free time and tell me what u think of it!
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