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Member
I am a New Artist
Duskfell
23/Female/United States
Why I Am Here
No reason given yet
Last Visit Unknown
Duskfall
Art Zone
Personal Zone
Misc. Zone
This is the place where you can personalize your profile!
But, how?
By moving, adding and personalizing widgets.
You can drag and drop to rearrange.
You can edit widgets to customize them.
The left side has widgets you can add!
Some widgets you can only access when you get a premium membership.
Some widgets have options that are only available when you get a premium membership.
We've split the page into zones!
Certain widgets can only be added to certain zones.
"Why," you ask? Because we want profile pages to have freedom of customization, but also to have some consistency. This way, when anyone visits a deviant, they know they can always find the art in the top left, and personal info in the top right.
Don't forget, restraints can bring out the creativity in you!
Now go forth and astound us all with your devious profiles!
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
I work at a camera store. It makes it much less pricey. The pay is poor, but the money you save is great. The 4x5 isn't mine, but I have unlimited borrowing power.
thank you for faving my Lomion V , also for your kind words and finally watching my arts
Angel
--
"A lot of people are afraid to say what they want.That's why they don't get what they want" SEX ~ Madonna
--
Did you know that:
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
--
Did you know that:
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
--
Squadalla! We're off!
--
Squadalla! We're off!
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